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Replies: 23
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110%er [7718]
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Actual Math Question
Dec 16, 2016, 10:16 AM
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How long in Minutes and Seconds will it take a the Clemson Bus travelling 90 MPH to catch a the Boom Bus traveling 60 MPH if the second bus has a 28.06 mile head start.
Message was edited by: Clemalum07®
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Starter [369]
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Just a guess, but is it
Dec 16, 2016, 10:18 AM
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56:07?
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110%er [7718]
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Re: Just a guess, but is it
Dec 16, 2016, 10:46 AM
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you are correct
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All-TigerNet [12943]
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All-In [37023]
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WOW!!!
Dec 16, 2016, 10:31 AM
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I thought his posting style was very familiar. Great catch Snowtown.
Do you think CM Shack knows you are on to him?
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Legend [16134]
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A million typos won't negate the fact that you came on here
Dec 16, 2016, 12:53 PM
[ in reply to the resident math expert is ] |
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and told everybody that you had insider info that we were jumping to the Big 12...you can change your name once a year and that stink is NEVER going away York
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Orange Blooded [2877]
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Re: Actual Math Question
Dec 16, 2016, 10:20 AM
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On i26 with traffic, I would guess roughly an 56:07
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All-TigerNet [10634]
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More like an M-60 Tank going 90 mph and a Yugo at 60!*****
Dec 16, 2016, 10:22 AM
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CU Medallion [64589]
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The first car has a 56.07 head start....
Dec 16, 2016, 10:22 AM
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the second car will most likely crash and burn before it ever has a chance to catch the first car.
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All-In [38427]
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Re: Actual Math Question
Dec 16, 2016, 10:25 AM
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Does the second car have gap insurance ?
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Orange Blooded [2836]
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Re: Actual Math Question
Dec 16, 2016, 10:28 AM
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I think the question is if 2 trains leave the train station at the same time how far will each travel in 60 minutes? Answer: The one painted orange would go 56 miles while the one painted red will travel 7 miles. so 56 to 7. Next question is what train do you want to be on? Answer: the Wayne Train. Go Tigers.
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Orange Blooded [4299]
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Re: Actual Math Question
Dec 16, 2016, 10:43 AM
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Yes, 56min and 7 seconds. The cars would pass each other at the Jalapa Rd exit on I-26 (84.18 miles away) if leaving Clemson headed towards Columbia, assuming they took the I-185 toll route.
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110%er [7885]
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Never
Dec 16, 2016, 11:43 AM
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The first car you mentioned is the 90 MPH car. Since it is moving faster and has a head start, it will never need to catch the second car. Sorry, I'm a math teacher.
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Rock Defender [53]
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Re: Never
Dec 16, 2016, 12:47 PM
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^^^Haha - I caught that too. Additionally, he did not ask to round the seconds to the nearest second, so I got 56:07.2
I'm not a math teacher, but I majored in math 40 years ago, so a little (ok - a lot) rusty. But we're gonna have to work on these millennials not being specific enough. We won't count off THIS time, but watch it buddy.
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110%er [7718]
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Re: Never
Dec 16, 2016, 12:55 PM
[ in reply to Never ] |
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Sorry I didn't dumb it down for you enough. The fact that the question clearly states that the 90 MPH is trying to catch the 60 MPH car it would be pretty easy to figure out that the car in front IE the car in "first" would be the slower car.
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Legend [16134]
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Yeah, it's the math teacher's fault you wrote it sh!tty***
Dec 16, 2016, 12:58 PM
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110%er [7718]
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Re: Yeah, it's the math teacher's fault you wrote it sh!tty***
Dec 16, 2016, 1:55 PM
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Aww look it is the guy who said 1.7<1.5 or some #### like that.
Go away.
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Legend [16134]
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Rock Defender [53]
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Re: Never
Dec 16, 2016, 1:30 PM
[ in reply to Re: Never ] |
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In the real math world, we don't make assumptions like that.  Just messing with ya'.
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Orange Blooded [4299]
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Re: Never
Dec 16, 2016, 2:46 PM
[ in reply to Never ] |
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Never is incorrect, too.
It is clear and unambiguous that the two cars started 28.06 miles apart. However, it didn't state that the cars were traveling in the same direction.
If the cars were traveling in the same direction, and the 60mph was "ahead", then the answer is 56m7s.
But if the 90mph car was ahead, the it would have to travel around the World to "lap" the 60 mph car. Assuming they are on the equator, that would take 49,745m53s.
If the 90mph car was traveling west, and the 60mph car was traveling east, it would take about 9,949m 11s for them to meet somewhere on the other side of the planet.
So, there's that.
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CU Guru [1327]
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Are these amphibious cars? :)***
Dec 16, 2016, 3:01 PM
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Commissioner [961]
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Re: Actual Math Question
Dec 16, 2016, 12:00 PM
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Where is the second car; which of the two is the first car. Like the old story of Pravda reporting the USA vs Russian drag race. The American finished next to last an the Russian finished second.
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Commissioner [960]
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Is this a euphimism
Dec 16, 2016, 1:59 PM
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for us and the coots? They will never catch us.
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All-In [30818]
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Is 1 of the cars a boom bus?***
Dec 16, 2016, 2:52 PM
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